java - How do I correctly get the largest and smallest numbers in a sequence of numbers? -

i'm supposed smallest , largest number out of sequence of numbers. know method body each method not right. help?

public class dataset {   private int sum;   private int count;   private int largest;   private int smallest;    public dataset()    {    sum = 0;    count = 0;    largest = 0;    smallest = 0;    }   public void addvalue(int x)   {    sum = sum + x;    count++;   }   public int getsum()  {    return sum;  }   public double getaverage()  {    double average = sum/count;    return average;  }   public int getlargest()  {    int largest = integer.max_value;//not giving right answer, don't know how use    return largest;  }    public int getsmallest()  {    int smallest = integer.min_value;//not giving right answer, don't know how use    return smallest;   } } 

---

here tester class if needed, although don't think problem lies here.

 public class datasettester  {      public static void main(string[] args)     {     dataset mydata = new dataset();     mydata.addvalue(100);     mydata.addvalue(5);     mydata.addvalue(4);     mydata.addvalue(2);      system.out.println("sum = " + mydata.getsum());     system.out.println("average = " + mydata.getaverage());     system.out.println("largest value = " + mydata.getlargest());     system.out.println("smallest value = " + mydata.getsmallest());    }    } 

integer.max_value , integer.min_value returns largest , smallest number representable integer value

instead, in add method, need comparing values added, can use math.min , math.max make comparison easier, example...

private int smallest = integer.max_value; private int largest = integer.min_value;  public void addvalue(int x) {     smallest = math.min(smallest, x);     largest = math.max(largest, x);     sum = sum + x;     count++; }