.pop() equivalent in scala -

i have worked on python in python there function .pop() delete last value in list , return deleted value ex. x=[1,2,3,4] x.pop() return 4

i wondering there scala equivalent function?

if wish retrieve last value, can call x.last. won't remove last element list, however, immutable. instead, can call x.init obtain list consisting of elements in x except last 1 - again, without changing x. so:

val lastel = x.last val rest = x.init 

will give last element (lastel), list of bar last element (rest), , still have original list (x).