c - Why doesn't the printout of this program stop at the 0 digit? -

c - Why doesn't the printout of this program stop at the 0 digit? -

#include <stdio.h> #include <stdlib.h>  int main(int argc, char* argv[]) { char* key="844607587";   while(*key!=0){  printf("hello world,%c\n",*key);  key++;} }

why doesn't program stop @ 0 digit? 0 mean? 1 without ' '

you made simple mistake - comparing (most ascii) characters in string numeric value 0. change:

while(*key!=0){

to

while(*key!='0'){

note numeric value 0 value of c string terminator, written '\0', code stops when reaches end of string, rather when sees character '0'.

Comments