c# - Most efficient way to read two nodes from multiple XML files? -


i'm looking fast , efficient way retreive 2 strings multiple xml files.

the files them selves aren't big 50kb 100kb , number of files can range none 100. i've included sample of small xml file i'll using. xml files same format , there's 2 things need know files namely:

    <company>test bv.</company>     <ship>sss testing</ship>

i want store these strings in struct/class since cannot use tuple in .net 3.5 (or mistaking?)

so question: efficient way this? using xdocument? using xmlreader? or else?

<?xml version="1.0" encoding="utf-8"?> <collection xmlns:xsi="http://www.w3.org/2001/xmlschema-instance" xmlns:xsd="http://www.w3.org/2001/xmlschema">   <customer>     <id>-1</id>     <updated>true</updated>     <company>test bv.</company>     <ship>sss testing</ship>     <adress>fggfgggff gvg</adress>     <city>fgcgg</city>     <zipcode>5454fc</zipcode>     <country>fcgggff</country>     <btw_nmbr>55</btw_nmbr>     <istempcustomer>true</istempcustomer>     <phonenumbers>       <contactdata>         <id>21</id>         <updated>true</updated>         <description>455656567</description>         <name>ghbbvh</name>         <issendable>false</issendable>       </contactdata>       <contactdata>         <id>22</id>         <updated>true</updated>         <description>2315098234146124302134</description>         <name>asdfawegaebf</name>         <issendable>false</issendable>       </contactdata>     </phonenumbers>     <emailadresses />   </customer>   <order>     <id>-1</id>     <updated>true</updated>     <ordernr>10330200</ordernr>     <orderdate>1-1-2005</orderdate>     <startdate>10-9-2013</startdate>     <expirationdate>20-10-2013</expirationdate>     <executor>andre de zwart</executor>     <executors />     <reference />     <orderdetail />     <isdigital>true</isdigital>   </order>   <materials>     <materialdata>       <id>108</id>       <updated>true</updated>       <description>ffdffggfg</description>       <amount>34</amount>     </materialdata>     <materialdata>       <id>109</id>       <updated>true</updated>       <description>ffccff</description>       <amount>45</amount>     </materialdata>   </materials>   <hourexpenses>     <hourexpensesdata>       <id>43850</id>       <updated>true</updated>       <date>2013-10-06t00:00:00</date>       <notes>lala</notes>       <day>sunday</day>       <hours>0.01</hours>       <businesshours>0.01</businesshours>       <travledhoursto>0</travledhoursto>       <travledhoursfrom>0</travledhoursfrom>       <start>2013-10-06t12:27:00</start>       <stop>2013-10-06t12:27:00</stop>     </hourexpensesdata>     <hourexpensesdata>       <id>43849</id>       <updated>true</updated>       <date>2013-09-17t00:00:00</date>       <notes>oke dus ik ben nu lekker aan het werk en ik typ wat spul er bij</notes>       <day>tuesday</day>       <hours>0</hours>       <businesshours>0.01</businesshours>       <travledhoursto>0</travledhoursto>       <travledhoursfrom>0</travledhoursfrom>       <start>2013-09-17t12:31:31</start>       <stop>2013-09-17t12:31:32</stop>     </hourexpensesdata>     <hourexpensesdata>       <id>43855</id>       <updated>true</updated>       <date>2013-10-03t00:00:00</date>       <notes>test</notes>       <day>thursday</day>       <hours>0</hours>       <businesshours>0</businesshours>       <travledhoursto>12</travledhoursto>       <travledhoursfrom>12</travledhoursfrom>       <start>0001-01-01t00:00:00</start>       <stop>0001-01-01t00:00:00</stop>     </hourexpensesdata>   </hourexpenses>   <travelexpenses>     <travelexpensesdata>       <id>672</id>       <updated>true</updated>       <date>2013-09-27t00:00:00</date>       <notes />       <kmto>45</kmto>       <kmfrom>45</kmfrom>       <declaration>0</declaration>     </travelexpensesdata>   </travelexpenses>   <signatures>     <id>-1</id>     <updated>true</updated>     <orderid>10330200</orderid>     <completed>false</completed>     <notes>yay het werkt ;d</notes>   </signatures>   <removeddatalist /> </collection>

i use linq xml in simplest possible way:

var query = file in files             let doc = xdocument.load(file)             customer in doc.descendants("customer")             select new {                company = (string) customer.element("company"),                ship = (string) customer.element("ship")             };

i'd expect pretty quick - should work out exact performance requirements are, test them. (you don't need "the efficient" way - need sufficiently efficient way, whilst keeping code readable.)

note if want values propagated out of current method, should create own class represent company/ship pair.


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