Complexity of inefficient divide and conquer algorithm -


an instance of size n divided p≥2 instances each of size n-a a small integer , p constant. computation cost of operation (i.e. dividing instances) unit, c(0)=1.

i trying find complexity of design. having trouble putting words equation, here think recursion should like:

c(n) = (n-a)*c(n/p) + 1

is correct?

i think this:

c(n) = (p)*c(n-a) + 1

my rationale said 'p≥2 instances each of size n-a' in question. size reduces c(n-a) , there p subproblems. think p*c(n-a). got other term right. cost of dividing @ each step c(0) = 1 said.


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