basic haskell : Converting Type to Int -

if have type, eg insurance number int.

is there anyway can convert insurancenumber int use in comparing function?

intni :: ni -> int intni x = int (x) 

if, suspect, ni defined as

type ni = int 

then can say

intni :: ni -> int intni x = fromintegral x 

or, after eta-conversion:

intni :: ni -> int intni = fromintegral 

---

on other hand, seems that

data ni = ni int 

in case right way go pattern matching, so:

intni (ni x) = x 

this extract x bit out of ni x , return it.