haskell - Ignoring letters and parsing only numbers using Parsec -


this code works when numerals (eg: "1243\t343\n") present:

tabfile = endby line eol line = sepby cell (many1 tab) cell = integer eol = char '\n'  integer = rd <$> many digit   rd = read :: string -> int

is there way make parse "abcd\tefg\n1243\t343\n" such ignores "abcd\tefg\n" part ?

you can skip except digits using skipmany. next:

many (skipmany (noneof ['0'..'9']) >> digit)

or (depending on need)

skipmany (noneof ['0'..'9']) >> many digit

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