php - Why isn't this form returning results? -


i have started trying learn php , mysql , have been following tutorials creating webpage search engine, have been experience issue wherein when submit form results aren't returned, have no idea problem lies or try , troubleshoot it, thought it'll worth shot post problem here. can me out, in advance.

php

<?php         mysql_connect("localhost","root","123")or die("could not connect db");     mysql_select_db("members") or die("could not find db");  if(isset($_post['submit'])){     $searchq = $_post['submit'];     $searchq = preg_replace("#[^0-9a-z]#i","",$searchq);     $query = mysql_query("select * memberlist fname '%$searchq%' or lname '%$searchq%'  ") or die(mysql_error());     $count = mysql_num_rows($query);    if($count == 0){     $output = "no results found, sorry."; }  else{     while($row = mysql_fetch_array($query)){         $firstname = $row['fname'];         $lastname = $row['lname'];         $output .= "<div>".$firstname." ".$firstname."</div>";     } } }  ?>

html

<!doctype html> <html lang="en"> <head>     <meta charset="utf-8">     <title>search</title> </head> <body>  <form action="index.php" method="post"> <input type="text" name="searchfname" placeholder="enter first name"> <input type="text" name="searchlname" placeholder="enter last name"> <input type="submit" name="submit" value="submit"> </form>  <?php print($output);?>  </body> </html>

you can use $_post['submit'] check if form submitted, not hold form values. can access separate form values respective name.

so use $_post['searchfname'] value in first textbox , $_post['searchlname'] second.

your code should read more this;

$searchqf = $_post['searchfname']; $searchql = $_post['searchlname']; $searchqfreplace = preg_replace("#[^0-9a-z]#i","",$searchqf); $searchqlreplace = preg_replace("#[^0-9a-z]#i","",$searchql); $query = mysql_query("select * memberlist fname '%$searchqf%' or lname '%$searchql%'  ") or die(mysql_error()); $count = mysql_num_rows($query);

notice way of composing queries insecure , vulnerable sql injection.

you're asking way troubleshoot. want echo , print_r.


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