post - how is that x=20;x= ++x + ++x + x++ ;final value of x in java is 65 -


this question has answer here:

how possible post increment operator should increase x 66?

when did same y= ++x + ++x + x++; gave value 65 y , 23 x.

so let me know how java compilers solving these expression.

let java show you. javap -c myclass shows bytecode:

  public static void main(java.lang.string[]);     code:        0: bipush        20        2: istore_1              3: getstatic     #2                  // field java/lang/system.out:ljava/io/printstream;        6: iinc          1, 1        9: iload_1              10: iinc          1, 1       13: iload_1              14: iadd                 15: iload_1              16: iinc          1, 1       19: iadd                 20: dup                  21: istore_1             22: invokevirtual #3                  // method java/io/printstream.println:(i)v       25: return

and result logical if think it: have 2 preincrements , 1 postincrement. so, code in effect:

y = 0  x++      // 21 y += x  x++      // 22 y += x  y += x   // (still 22!) x++      // 23  x = y    // (21 + 22 + 22 @ point)

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