The code won't recognize my if statement (Python) -


the code wont recognize if statement. when run code, enter following number: -10. however, returns else statement, when should return if statement. doing wrong?

def distance_from_zero(d):     if type(d)== int or type(d)==float:         return abs(d)     else:         return "not integer or float!" x = raw_input("enter number: ")         print distance_from_zero(d)

raw_input returns string. if type number 9, doesn't return integer 9, returns string "9". therefore test type(d)== int or type(d)==float never true.

you 

def distance_from_zero(d):     try:         return abs(int(d))     except valueerror:         pass     try:         return abs(float(d))     except valueerror:         pass     return "not integer or float!" x = raw_input("enter number: ")         print distance_from_zero(x)

this makes use of design philosophy popular in python called "duck typing", in which, rather test see object's type is, treat object whatever type want , handle exception pops if isn't type.


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