AWK - How to do the sorting? -


in awk, how can this: 

1303361997;15;67.067014 1303361997;5;51.529837 1303361997;14;47.036197 1303361997;3;44.064681 1303361997;6;37.632831 1303361997;23;24.990078 1303361997;24;26.750984 1303361998;15;67.074100 1303361998;5;51.522981 1303361998;14;47.028185 1303361998;3;44.056715 1303361998;6;37.638584 1303361998;23;24.987800 1303361998;24;26.756648

when number in second columns absent date should replace 0 in output file. first place number of first column. values ​​of second column of data determine position of third column in output file. first column each time may begin different values. desired output, sorting first , second columns: 

1303361997;0;0;44.064681;0;51.529837;37.632831;0;0;0;0;0;0;0;47.036197;67.067014;0;0;0;0;0;0;0;24.990078;26.750984; 1303361998;0;0;44.056715;0;51.522981;37.638584;0;0;0;0;0;0;0;47.028185;67.074100;0;0;0;0;0;0;0;24.987800;26.756648; 

$ cat tst.awk begin { fs=";" } nr == 1 {     (i=1;i<=2;i++) {         min[i] = max[i] = $i     } } {     val[$1,$2] = $3     keys[$1]     (i=1;i<=2;i++) {         min[i] = ($i < min[i] ? $i : min[i])         max[i] = ($i > max[i] ? $i : max[i])     } } end {     (r=min[1];r<=max[1];r++) {         if (r in keys) {             printf "%d",r             (c=1;c<=max[2];c++) {                 printf ";%s", ((r,c) in val ? val[r,c] : 0)             }             print ";"         }     } } $ $ cat file 1303361997;15;67.067014 1303361997;5;51.529837 1303361997;14;47.036197 1303361997;3;44.064681 1303361997;6;37.632831 1303361997;23;24.990078 1303361997;24;26.750984 1303361998;15;67.074100 1303361998;5;51.522981 1303361998;14;47.028185 1303361998;3;44.056715 1303361998;6;37.638584 1303361998;23;24.987800 1303361998;24;26.756648 $ $ awk -f tst.awk file 1303361997;0;0;44.064681;0;51.529837;37.632831;0;0;0;0;0;0;0;47.036197;67.067014;0;0;0;0;0;0;0;24.990078;26.750984; 1303361998;0;0;44.056715;0;51.522981;37.638584;0;0;0;0;0;0;0;47.028185;67.074100;0;0;0;0;0;0;0;24.987800;26.756648;

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