PHP arrays, trying to match three numbers -


im trying match 3 or more numbers 2 seperate arrays, have far code matching first 3 numbers, when need compare 6 numbers , see if there 3 in common ? have tried comparing 6 numbers not work. appreciated. jessica

foreach($lottotickets $y => $yvalue) {    if($i == 0) {     echo " "; } else{     if((($winner[0] == $lottotickets[$y][0]) || ($winner[0] ==   $lottotickets[$y][1]) || ($winner[0] == $lottotickets[$y][2]) || ($winner[0] == $lottotickets[$y][3]) || ($winner[0] == $lottotickets[$y][4]) || ($winner[0] == $lottotickets[$y][5])) &&      (($winner[1] == $lottotickets[$y][0]) || ($winner[1] == $lottotickets[$y][1]) || ($winner[1] == $lottotickets[$y][2]) || ($winner[1] == $lottotickets[$y][3]) ||($winner[1] == $lottotickets[$y][4]) || ($winner[1] == $lottotickets[$y][5])) &&     (($winner[2] == $lottotickets[$y][0]) || ($winner[2] == $lottotickets[$y][1]) || ($winner[2] == $lottotickets[$y][2]) || ($winner[0] == $lottotickets[$y][3]) ||($winner[2] == $lottotickets[$y][4]) || ($winner[2] == $lottotickets[$y][5])))      echo "<b>three winning numbers id = </b>" .$y; } 

you use array_diff() purpose. returns array containing differences within 2 given arrays.

if determine differences between user's lotto ticket , correct numbers, amount of wrong numbers.

subtracting integer 6* gives amount of correctly chosen numbers.

foreach ($lottotickets $y => $yvalue) {   if($i == 0)   {     echo " ";   }    else {     $diff = array_diff($lottotickets[$y], $winner);     $correctnumbers = 6 - count($diff);      if ($correctnumbers >= 3) {       echo "<b>(at least) 3 winning numbers id = </b>" . $y;     }   } } 

here minimal working sample: http://codepad.org/owrdv5xe

*) 6 not magic number here (→ lotto)


as why code not work (in cases): because compare first 3 correct numbers chosen ones. have compare numbers. involves having counter variable storing amount of correctly chosen numbers.

if want stick current solution, @ least use in_array() , loop. but solution provided @ top of answer better.


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