Sorting and swapping elements in two ArrayLists (Java) -


i new java...

i have 2 arraylists:

sublist1 sublist2

they have been populated method , when run, lists contain following strings:

sublist1: [amulet, map, stone, sword] sublist2: [bottle, shield, wand]

what need able sort both lists sublist1 contains elements smaller elements in sublist2 in terms of alphabetical postion. both list sizes must stay same.

expected output:

sublist1: [amulet, bottle, map, shield] sublist2: [stone, sword, wand]

my code far:

collections.sort(sublist1); collections.sort(sublist2);      //[amulet, map, stone, sword]     //[bottle, shield, wand]      (int i1 = 0; i1 < sublist1.size(); i1++) {          (int i2 = 0; i2 < sublist2.size(); i2++) {          if (sublist1.get(i1).compareto(sublist2.get(i1)) < 0) {              // first run: element 0: sublist1 = amulet, sublist2 = bottle              string temp = sublist1.get(i1);             sublist1.set(i1, sublist2.get(i1));             sublist2.set(i1, sublist1.get(i1));

i indexoutofboundsexception following line:

if (sublist1.get(i1).compareto(sublist2.get(i1)) < 0)

any appreciated. thanks.

you complicating task sorting 2 lists separately, , iterating on them. suggest follow approach:

  • merge 2 list create newlist = sublist1 + sublist2
  • sort newlist
  • get sublist equal length of sublist2 end of newlist.
  • get sublist equal length of sublist1 beginning of newlist

working code:

collection<string> sublist1 = arrays.aslist("amulet", "map", "stone", "sword"); collection<string> sublist2 = arrays.aslist("bottle", "shield", "wand");  // merge 2 collection in single list     list<string> mergedlist = new arraylist<>(sublist1); mergedlist.addall(sublist2);  collections.sort(mergedlist);  // assign sublist mergedlist original collection reference sublist1 = mergedlist.sublist(0, sublist1.size()); sublist2 = mergedlist.sublist(sublist1.size(), mergedlist.size());  system.out.println(sublist1);  // [amulet, bottle, map, shield] system.out.println(sublist2);  // [stone, sword, wand]

Comments

Post a Comment

Popular posts from this blog

c++ - CryptStringToBinary API behavior -

i seeing strange behavior cryptstringtobinary cryptography api. please see below code (config: x64 debug): #include "stdafx.h" #include <windows.h> #include <strsafe.h> #include <iostream> #include <exception> void main() { dword dwskip; dword dwflags; dword dwdatalen; //lpcwstr pszinput = l"jaaaaaecaaadzgaaakqaagdnnl1l56bwgfjdgr3rpxtqqqn6daw3usv2emkjym4t"; //this works fine lpcwstr pszinput = l"mytest"; //doesnt work, api returns false,error code 0x0000000d // determine size of byte array , allocate memory. if(! cryptstringtobinary( pszinput, _tcslen( pszinput ) + 1, crypt_string_base64, null, &dwdatalen, &dwskip, &dwflags ) ) { dword dw = getlasterror(); //0x0000000d: data invalid throw std::exception( "error computing byte length." ); } byte *pbytebyte = null; try { ...
Read more

java.util.scanner - How to read and add only numbers to array from a text file -

i'm learning java , have question regarding reading file want read numbers file contains strings well. here example of file: 66.56 "3 java 3-43 5-42 2.1 1 and here coding: public class test { public static void main (string [] args){ if (0 < args.length) { file x = new file(args[0]); try{ scanner in = new scanner( new fileinputstream(x)); arraylist<double> test = new arraylist<>(); while(in.hasnext()){ if(in.hasnextdouble()){ double f=in.nextdouble(); test.add(f);} else {in.next();} } catch(ioexception e) { system.err.println("exception during reading: " + e); } } my problem add 66.56,2.1 , 1 doesn't add 3 after "3 or ignores 3-43 , 5-42 can tell me how skip strings , add doubles here? thanks all said 3 ie; "3, 3-43 , 4-42 strings either u read string , split , check number @ " , - or put in space between characters , integers. jvm after compilation tre...
Read more

iphone - Three second countdown in cocos2d -

i trying have 3 second countdown display when level beat in game. did: -(void) gamesegmentbeat { [self pauseschedulerandactions]; // overlay game opaque background ccsprite *opaquebg = [ccsprite spritewithfile:@"background1.png"]; opaquebg.position = screencenter; [self addchild:opaquebg z:10000]; // these 3 labels 3 seconds cclabelttf *three = [cclabelttf labelwithstring:@"3" fontname:@"helvetica" fontsize:100]; three.position = ccp(screencenter.x, screencenter.y); cclabelttf *two = [cclabelttf labelwithstring:@"2" fontname:@"helvetica" fontsize:100]; two.position = ccp(screencenter.x, screencenter.y); cclabelttf *one = [cclabelttf labelwithstring:@"1" fontname:@"helvetica" fontsize:100]; one.position = ccp(screencenter.x, screencenter.y); // secondspast specified in update method secondspast = 0; if (secondspast == 1) { [self addchild:thr...
Read more